This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Problem 1.6 A certain cross section lies in the x y plane. If 3 10 20 electrons go through the cross section in the z-direction in 4 seconds, and simultaneously, 1 . 5 10 20 protons go through the same cross section in the negative z-direction, what is the magnitude and direction of the current flowing through the cross section? Solution: Negatively charged electrons moving along + z-direction constitute a current in the- z-direction: I e = Q t = 3 10 20 1 . 6 10- 19 4 = 12 A, along- z-direction . Positively charged protons moving along- z-direction constitute a current in the- z-direction: I p = Q t = 1 . 5 10 20 1 . 6 10- 19 4 = 6 A, along- z-direction . Total net current is: I = I e + I p = 12 + 6 = 18 A, along- z-direction. Problem 1.18 For each of the seven devices in the circuit of Fig. P1.18, determine whether the device is a supplier or a recipient of power and how much power it is supplying or receiving....
View Full Document
- Fall '06
- Electrical Engineering