HW _7 Solutions - Th venin and Norton Equivalents e Problem...

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Th´evenin and Norton Equivalents Problem 3.51 Find the Th´evenin equivalent circuit at terminals ( a , b ) for the circuit in Fig. P3.51. 1 Ω 2 Ω 3 Ω 4 Ω 2 Ω 3 A a b V oc V + _ Figure P3.51: Circuit for Problem 3.51. Solution: V 3 + V 6 = 3 V = 6 V . Voltage division gives V Th = V oc = V 6 × 4 = 4 V . Suppressing the current source: 1 Ω 2 Ω 3 Ω 4 Ω 2 Ω a b R Th R Th R Th 5 Ω 3 Ω 4 Ω a b 3 Ω Ω a b 20 9 R Th = 3 + 20 9 = 47 9 = 5 . 2 . Th´evenin equivalent circuit: 5.2 Ω a b 4 V + _
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Problem 3.52 Find the Th´evenin equivalent circuit at terminals ( a , b ) for the circuit in Fig. P3.52. 2.5 4 6 3 4 A 2 V a b + _ V oc V + _ Figure P3.52: Circuit for Problem 3.52. Solution: V 4 + V 6 + V 2 3 = 4 Hence, V = 56 9 V. V Th = V oc = V 2 = 56 9 2 = 4 . 22 V . Suppressing the sources: 2.5 4 6 3 a b 2.5 a b 4 3 R Th R Th R Th = 4 3 + 2 . 5 = 3 . 83 Th´evenin equivalent circuit: 3.83 4.22 V a b _
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Problem 3.54
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This note was uploaded on 06/15/2011 for the course EE 302 taught by Professor Mccann during the Fall '06 term at University of Texas at Austin.

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HW _7 Solutions - Th venin and Norton Equivalents e Problem...

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