{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW _7 Solutions

# HW _7 Solutions - Th venin and Norton Equivalents e Problem...

This preview shows pages 1–4. Sign up to view the full content.

Th´evenin and Norton Equivalents Problem 3.51 Find the Th´evenin equivalent circuit at terminals ( a , b ) for the circuit in Fig. P3.51. 1 Ω 2 Ω 3 Ω 4 Ω 2 Ω 3 A a b V oc V + _ Figure P3.51: Circuit for Problem 3.51. Solution: V 3 + V 6 = 3 V = 6 V . Voltage division gives V Th = V oc = V 6 × 4 = 4 V . Suppressing the current source: 1 Ω 2 Ω 3 Ω 4 Ω 2 Ω a b R Th R Th R Th 5 Ω 3 Ω 4 Ω a b 3 Ω Ω a b 20 9 R Th = 3 + 20 9 = 47 9 = 5 . 2 . Th´evenin equivalent circuit: 5.2 Ω a b 4 V + _

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem 3.52 Find the Th´evenin equivalent circuit at terminals ( a , b ) for the circuit in Fig. P3.52. 2.5 4 6 3 4 A 2 V a b + _ V oc V + _ Figure P3.52: Circuit for Problem 3.52. Solution: V 4 + V 6 + V 2 3 = 4 Hence, V = 56 9 V. V Th = V oc = V 2 = 56 9 2 = 4 . 22 V . Suppressing the sources: 2.5 4 6 3 a b 2.5 a b 4 3 R Th R Th R Th = 4 3 + 2 . 5 = 3 . 83 Th´evenin equivalent circuit: 3.83 4.22 V a b + _
Problem 3.54 For the circuit in Fig. P3.53, find the Th´evenin equivalent circuit as seen by the 6- resistor connected between terminals ( c , d ) as if the 6-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}