CH302 Chapter 17 answers

CH302 Chapter 17 answers - Mole Fraction Concentration...

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Concentration example: Calculate the molality and the molarity of an aqueous solution that is 10.0% by mass glucose, C 6 H 12 O 6 . Then calculate the mole fraction of glucose. The density of the solution is 1.04 g/mL. 1 mol C 6 H 12 O 6 = 180 g. 1. ‘10% glucose’ means in 100g solution, 90g is water. 6 12 6 6 12 6 6 12 6 6 12 6 2 6 12 6 O H C 578 . 0 O H C g 180 O H C mol 1 L 1 mL 1000 n sol' mL 1 n sol' g 04 . 1 n sol' g 100.0 O H C g 0 . 10 O H L O H C mol ? M u u u 6 12 6 6 12 6 6 12 6 2 2 2 6 12 6 2 6 12 6 O H C 617 . 0 O H C g 180 O H C mol 1 O H kg 1 O H g 1000 O H g 90.0 O H C g 0 . 10 O H kg O H C mol ? m u u Molality : Molarity : NOTE: these are different, but IF (big IF) the aqueous solution was DILUTE enough, the density of the solution is then close to 1g/mL, and they will come out the same. Mole Fraction What are the mole fractions of glucose and water in a 10.0% glucose solution? ‘10% glucose’ means in 100g solution, 90g is water. O
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This note was uploaded on 06/13/2011 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas at Austin.

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CH302 Chapter 17 answers - Mole Fraction Concentration...

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