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Unformatted text preview: 1 0 . Next we subtract three times row two from row three to obtain 1 1 1 0 1 h-1 0 0 h 2-3 h + 2 0 . Observe that x 1 and x 2 are not free variables since there are pivots in the rst and second column. The variable x 3 is free if and only if h 2-3 h + 2 = 0. Factoring, we see if h = 2 or h = 1 then we have a free variable and hence the system has more than one solution in these cases. 1...
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