Week4 - 1 1 1 h-1 h h 2-1 h 2 + 2 h . Now we take care of...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Solutions for Assignment 4 Applied Linear Algebra MATH 232 (Fall 2008) Section 2.1 Section 2.2
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Assignment 4 Applied Linear Algebra Math 232(Fall 2008) Additional question: For which values of h is the matrix 1 1 1 1 h h + 1 1 h 2 h 2 + 2 h + 1 invertible A1. The matrix is invertible if and only if it has a pivot in every row and column. We row reduce, first using the pivot in the first column.
Background image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 1 1 h-1 h h 2-1 h 2 + 2 h . Now we take care of the second column: 1 1 1 h-1 h h . Observe that we have a pivot in every column if and only if h 6 = 1 , 0. Thus the matrix is invertible whenever h 6 = 0 , 1. 1...
View Full Document

Page1 / 3

Week4 - 1 1 1 h-1 h h 2-1 h 2 + 2 h . Now we take care of...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online