This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: ~ u 1 and ~ u 2 . This give Proj W ~v = ~v · ~ u 1 ~ u 1 · ~ u 1 u 1 + ~v · ~ u 2 ~ u 2 · ~ u 2 u 2 . This is equal to 4 / 11 ~ u 11 / 11 ~ u 2 . Thus the projection vector is b v = 3 / 11 7 / 11 7 / 11 16 / 11 . Let ~ z = ~vb v . Then ~ z is orthogonal to W and is in the span of ~v, ~ u 1 , ~ u 2 . Computing this, we ﬁnd 1 ~ z = 8 / 11 4 / 11 4 / 115 / 11 . Note that any nonzero scalar multiple of ~ z will also work. 2...
View
Full Document
 Fall '10
 Russel
 Linear Algebra, Algebra, Addition, Vector Space, u2

Click to edit the document details