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# 30 - hernandez(ejh742 oldhomework 30 Turner(58120 This...

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hernandez (ejh742) – oldhomework 30 – Turner – (58120) 2 Differentiating the x component of the par- ticle’s velocity with respect to t , we find the x component of the particle’s acceleration at any time t a x = d v x dt = - ω 2 A cos( ω t + φ ) , so at t = 1 . 44 s , the x component of the particle’s acceleration is a x = - ω 2 R cos φ 2 = - (13 rad / s) 2 (4 . 8 m) cos(19 . 9948 rad) = - 334 . 862 m / s 2 . 004 (part 1 of 3) 10.0 points Consider a uniform rod with a mass m and length L pivoted on a frictionless horizontal bearing at a point O parenleftbigg 5 8 L from the lower end parenrightbigg , as shown. 5 8 L L O θ What is the moment of inertia of the rod about the pivot point O ? The moment of inertia of a uniform rod about its center of mass is 1 12 M L 2 .
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30 - hernandez(ejh742 oldhomework 30 Turner(58120 This...

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