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Unformatted text preview: hernandez (ejh742) homework 32 Turner (58120) 1 This printout should have 16 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 4) 10.0 points A traveling wave propagates according to the expression y = (2 . 18 cm) sin bracketleftBig (1 . 99 cm 1 ) x (4 . 3 s 1 ) t bracketrightBig , where x is in centimeters, and t is in seconds. Find the amplitude of the wave. Correct answer: 2 . 18 cm. Explanation: Let : A = 2 . 18 cm . Given a wave y = A sin( k x t ), the ampli tude of the wave is A = 2 . 18 cm . 002 (part 2 of 4) 10.0 points Determine the wavelength of the wave. Correct answer: 3 . 15738 cm. Explanation: Let : k = 1 . 99 cm 1 . The angular wave number of the wave is k , so = 2 k = 2 1 . 99 cm 1 = 3 . 15738 cm . 003 (part 3 of 4) 10.0 points Determine the frequency of the wave. Correct answer: 0 . 684366 Hz. Explanation: Let : = 4 . 3 s 1 . The angular frequency of the wave is , so f = 2 = 4 . 3 s 1 2 = . 684366 Hz . 004 (part 4 of 4) 10.0 points Determine the period of the wave. Correct answer: 1 . 46121 s. Explanation: The period of the wave is T = 1 f = 1 . 684366 Hz = 1 . 46121 s . 005 10.0 points A wave on a string is described by the wave function y = (0 . 1 m) sin[(0 . 5 rad / m) x (20 rad / s) t ] Determine the frequency of oscillation of a particular point at x = 2 . 0 m. Correct answer: 3 . 1831 Hz. Explanation: Let : = 20 rad / s . In fact, when a wave with frequency f trav els along a string, any point of the string has the same oscillation frequency f . In this case, f = 2 = 20 rad / s 2 = 3 . 1831 Hz keywords: 006 (part 1 of 2) 10.0 points A steel piano wire is 0 . 7 m long and has a mass of 40 g. It is stretched with a tension of 400 N. What is the speed of transverse waves on the wire?...
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This note was uploaded on 06/14/2011 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.
 Spring '08
 Turner
 Physics, Work

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