to (aqt73) – Challenge 6 – seckin – (54330)
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001 (part 1 of 2) 10.0 points
Determine the quadrant in which the angle
lies.
a) 1
.
893 radians.
1.
None of these
2.
Quadrant III
3.
Quadrant II
correct
4.
Quadrant I
5.
Quadrant IV
Explanation:
Since
1
2
π <
1
.
893
< π
, then the angle of
1
.
893 radians lies in Quadrant II.
002 (part 2 of 2) 10.0 points
b)

0
.
353 radians.
1.
Quadrant II
2.
Quadrant IV
correct
3.
Quadrant III
4.
None of these
5.
Quadrant I
Explanation:
Since

1
2
π <

0
.
353
<
0, then the angle of

0
.
353 radians lies in Quadrant IV.
003
10.0 points
Evaluate
f
(
x
) = 3 sin
x

cos 2
x
at
x
=
π/
6.
1.
f
(
π/
6) = 3
2.
f
(
π/
6) = 1
correct
3.
f
(
π/
6) = 3
√
3
4.
f
(
π/
6) =
√
3
5.
f
(
π/
6) = 2
√
3
6.
f
(
π/
6) = 2
Explanation:
Since
sin
π
6
= cos
π
3
=
1
2
,
we see that
f
parenleftBig
π
6
parenrightBig
=
1
2
( 3

1 ) = 1
.
004
10.0 points
Evaluate
f
(
x
) = 5 sin
x
+ 3 cos
1
2
x
at
x
=
π/
3.
1.
f
(
π/
3) = 5
√
3
2.
f
(
π/
3) = 4
3.
f
(
π/
3) = 4
√
3
correct
4.
f
(
π/
3) = 5
5.
f
(
π/
3) = 6
6.
f
(
π/
3) = 6
√
3
Explanation:
Since
sin
π
3
= cos
π
6
=
√
3
2
,
we see that
f
parenleftBig
π
6
parenrightBig
=
√
3
2
( 5 + 3 ) = 4
√
3
.
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 Spring '11
 Cathy
 Trigonometry, Sin, quadrant

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