Quiz 5-solutions

# Quiz 5-solutions - Version 483 Quiz 5 laude (50995) 1 This...

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Unformatted text preview: Version 483 Quiz 5 laude (50995) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. Constants R = 8 . 314 J K 1 mol 1 RT 2 . 5 kJ mol 1 (at STP) Equations PV = nRT G = H- T S H rxn = summationdisplay products H f- summationdisplay reactants H f summationdisplay reactants BE- summationdisplay products BE U = q + w q = mc T w =- n gas RT 001 5.0 points Calculate the change in enthalpy for the following reaction, using the bond enthalpy data provided below. (Note: you may round the bond energies to the nearest 100 kJ mol 1 during your calculations) 2N 2 H 2 (g) + 3O 2 (g) 4NO(g) + 2H 2 O(g) Bond Bond Energy (kJ mol 1 ) N N 409 N H 388 O O 496 N O 630 O H 463 1.- 514 kJ mol 1 correct 2.- 1 , 531 kJ mol 1 3. 1 , 166 kJ mol 1 4. 514 kJ mol 1 5. 1 , 531 kJ mol 1 6.- 1 , 166 kJ mol 1 Explanation: H rxn = BE reactants- BE products = 2 409 kJ mol 1 + 4 388 kJ mol 1 +3 496 kJ mol 1- 4 630 kJ mol 1- 4 463 kJ mol 1 =- 514 kJ mol 1 002 5.0 points Approximate the work for the following re-...
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## This note was uploaded on 06/14/2011 for the course MATH 305G taught by Professor Cathy during the Spring '11 term at University of Texas at Austin.

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Quiz 5-solutions - Version 483 Quiz 5 laude (50995) 1 This...

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