Section 3.5-solutions-1

Section 3.5-solutions-1 - troyer(lmt836 Section 3.5...

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troyer (lmt836) – Section 3.5 – isaacson – (55826) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points ±ind the derivative oF f ( x ) = 2 x sin4 x + 1 2 cos 4 x . 1. f ( x ) = - 8 x cos 4 x 2. f ( x ) = 8 x cos 4 x - 4 sin 4 x 3. f ( x ) = 8 cos 4 x 4. f ( x ) = 8 x cos 4 x + 4 sin 4 x 5. f ( x ) = 8 x cos 4 x correct Explanation: Since d dx sin x = cos x, d dx cos x = - sin x, it Follows that f ( x ) = 2 sin4 x + 8 x cos4 x - 2 sin4 x. Consequently, f ( x ) = 8 x x . 002 10.0 points ±ind f ( x ) when f ( x ) = 1 x 2 - 6 x . 1. f ( x ) = 3 - x ( x 2 - 6 x ) 3 / 2 correct 2. f ( x ) = x - 3 (6 x - x 2 ) 1 / 2 3. f ( x ) = x - 3 ( x 2 - 6 x ) 3 / 2 4. f ( x ) = x - 3 (6 x - x 2 ) 3 / 2 5. f ( x ) = 3 - x ( x 2 - 6 x ) 1 / 2 6. f ( x ) = 3 - x (6 x - x 2 ) 3 / 2 Explanation: By the Chain Rule, f ( x ) = - 1 2( x 2 - 6 x ) 3 / 2 (2 x - 6) . Consequently, f ( x ) = 3 - x ( x 2 - 6 x ) 3 / 2 . 003 10.0 points Determine f ( x ) when f ( x ) = 1 + x 1 - 2 x 2 . 1. f ( x ) = - 1 + 2 x (1 - 2 x 2 ) 1 / 2 2. f ( x ) = 1 + 2 x (1 - 2 x 2 ) 1 / 2 3. f ( x ) = 1 - 2 x (1 - 2 x 2 ) 3 / 2 4. f ( x ) = 1 + 2 x (1 - 2 x 2 ) 3 / 2
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Section 3.5-solutions-1 - troyer(lmt836 Section 3.5...

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