Homework2Solns

Homework2Solns - SHORT CALCULUS Math 16C Sec 2 Spring 2008...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: SHORT CALCULUS Math 16C Sec 2 Spring 2008 Homework #2 Solutions Peter Malkin Section C.4 Question 8 The differential equation is dP dt = kP where k is some constant. We can find the general solution using the separation of variables technique. dP dt = kP 1 P dP = kdt integraldisplay 1 P dP = integraldisplay kdt ln( P ) = kt + C P = e kt + C P = Ae kt where C and A are constants. The general solution is P = Ae kt . Let t = 0 in 1998. So, 400 , 000 = Ae A = 400 , 000. Thus, the particular solution is P = 400 , 000 e . 015 t . In 2005, the population is P = 400 , 000 e . 015(7) 444 , 284. Question 28 Let Q be the amount of concentrate in the tank at time t . At any point in time, there is 0lbs/min of concentrate flowing into the tank, and there is 5 Q 100 = Q 20 lbs/min flowing out of the tank. Thus, the rate of change of Q over time is dQ dt = 0- Q 20 . We can find the general solution using the separation of variables technique. We could also use the LINFODE technique....
View Full Document

Page1 / 4

Homework2Solns - SHORT CALCULUS Math 16C Sec 2 Spring 2008...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online