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# Q2aSol - [Marks I10 AMath 250 N81116 Quiz#2 Version...

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Unformatted text preview: [Marks] I10} AMath 250 N81116:-.. _ ___ -. _ Quiz #2, Version “0:” ID# 1. Use the Laplace transform method to solve the initial value problem y” + 23/ + log = sat, y(0) = O, 3/(0) =1. Ami: Bay”\$310)~3'(o)]+2fs\/'j(°))+{oY 532 \ H s“ ‘ I S a f: .I" M W (3%“ “0W ‘ \ + 5% = 5 * 5" f3 5 59‘ {yr “4 3- 97 \HS) :3 £3.52...“ /; 53(5 Kano) , TM) W on gouge) (AM- “We, ”(RA Lad-{M Aumfvsﬂa‘on 3~ as 5 +50 ~ A + B * Cs+D {25“ - a... a... M (1’: "I_ \$a(\$a¥39¥{°) S g“ gay-3“,", ‘ TR» (mum, ﬂ“; \$3.50 _ S '. : loA'rQB I ‘0 A34 3 S: 1=QA+B?D 5, D:.. 3 . S 0: AM, , so C= (fix! 3 fi/ Wk“) we 31d Adam)" \/(s)= g-..‘._ + \$4 *3 T-~ S S 5+15H0 {:3 = '5'; ~ 3- + S”; :3 5 5 KSHYH \ 3 .. .. : -5;__\_+(s+;)a3 u U S S {9‘0“} .. ‘6 3/”.X 5» 3H): S£-l 4» eeco53£ '— € Siagf, {9.3) <ch}xntca.\\3, 0b" mm c} So‘uVOA IS Kit-hi 04:) {W {:20} \am" 3»- (An 60-5“) maﬁa HA M Our “\$er (parks L” Q} 4:.) I10} 2. Use the Laplace transform method to solve the initial value problem y’+ y = f(t), ,y(0) = 0, where m) = {38mm f: j : {3:33) @- Hint: sin(t) == —sin(t — 7r), and cos(t) == ~ cos(t — 7:). \Je, we, 53“,. 3].? b = 2923c [WW- HH-‘T‘ﬁ \} (g) = 2533c HM - QS‘mi Wk“) ; == Qszakwe) + :2 wmzem). > A66 1 Q» a -15, kc: 3 53’ + 7 w e 53H 3, 55H .. g -115 5° W * \+e . KSH§<§2+H [ ] Decomeoav. '“w (“RNA esrcessicw .31.? a A + 85% {if} (\$H\(s +\\ SH 3344 ==7 2 = A83“) + (1590“?!) \ Sew? S='\ 5M5 7,1: 2A / {0 A24 :; 1x. 3* 5W; 32% 0: mg, so guy 4/ TL: So +um5 32W, 2: [OH-C, So C", 5H 5H 5% We new) have. Y( s): {i as. + %](1+€_“S) Mg“, 3% (gt, we J, M) + (8-H- mumMmﬁww R; r ;\i '3 €v£~cos£+§xo~£ 4— (eMe, +cos{i—'Sin{)\’\(”{: 1‘) VVVVVV —.-.. 540k +5“ch , £0! £6035” (“a“)éi ‘1‘" {:é EEOC) ‘ I I: (SW11 ”05% {I ‘-‘”K£~3€}} ...
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Q2aSol - [Marks I10 AMath 250 N81116 Quiz#2 Version...

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