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DQ7A_solution - Discussion Question 7A P212 Week 7 RC...

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Discussion Question 7A P212, Week 7 RC Circuits The circuit shown initially has the capacitor uncharged, and the switch connected to neither terminal. At time t = 0, the switch is thrown to position a. (a) At t = 0+, immediately after the switch is thrown to position a, what are the currents I 1 and I 2 across the two resistors? What does the uncharged capacitor look like to the rest of the circuit at time 0? Does it offer any resistance to the flow of charge? (Why or why not?) 2 2 At t = 0, the capacitor acts like wire w/ no resistance to current flow. Hence the battery is effectively hooked to 6 / 12 /6 2 A = Ω ⇒ = = Ω = R I R V (b) After a very long time, what is the instantaneous power P dissipated in the circuit? After a very long time, what will have happened to the capacitor? Now what will it look like to the rest of the circuit? ( ) ( ) 1 2 1 2 After a long time the capacitor acts like an open circuit and the battery current flows through . Hence I = /( .) = 12/9 =4/3 A and the power is 12 4/3 16 + + = = × = R R R R P I V A W E E (c)

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DQ7A_solution - Discussion Question 7A P212 Week 7 RC...

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