{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

DQ8A_solution - Discussion Question 8A P212 Week 8 Magnetic...

This preview shows pages 1–2. Sign up to view the full content.

Discussion Question 8A P212, Week 8 Magnetic Forces and Torques on Loops A triangular loop with hypotenuse a and 30 ˚ - 60 ˚ - 90 ˚ angles lies in the xy plane. A constant current I circulates clockwise around the loop, and a uniform magnetic field of strength B points in the + x direction. (a) Calculate the forces on each of the three sides of the current loop ( AB , BC , and CA ), and sum them to find the net force on the loop. Remember that you will be adding vectors , so express each force in terms of its components. Since dF=i d , the force will to both d and which means it will lie along or against the Z axis for each current segment. By the right-hand rule the force on AB segment will point into th B B × G G G G G A A AB ˆ e plane of the paper or in the -z direction ; while the force on ˆ the AC segment will point into the plane of the paper or in the +z direction. Since B is we have F =Bi =(0.04 T)(5 A) (0.03 AB AB G G A A 0 0 0052 0 60 0 0052 0 0 0 CA ˆ m cos 30 ) . Since segment BC is || to B its force vanishes because of cross prod ˆ Segment CA is at 60 wrt B thus F =Bi

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 3

DQ8A_solution - Discussion Question 8A P212 Week 8 Magnetic...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online