Oct 15, 2010 - 8(.125) = 1.000 Events Heads and Tails are...

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ectively Exhaustive Set of Events Chapter 4 Experiment Sample Points Sample Space 1. Venn Diagram 2. Probability Tree 3. Apply Rules 4. Contingency Table Find probability of 2 heads out of 3 coins . Sample Point Probability H3 / H1H2 1 P( H1H2H3) H = Heads .5 T= Tails .5 H2 / H1 .5 T3/H1H2 2 P(H1H2T3) H1 .5 .5 H3 / H1H2 3 P(H1T2H3) . .5 T2/ H1 . 4 H1T2T3 .5 T1.5 H2/T1 . 5 T1H2H3 .5 T2 / T1 . 6 T1H2T3 | 7 T1T2H3 Conditional Probability 8 T1T2T3 # Heads Prob 0 .125
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1 3(.125) 2 3(.125) 3 .125
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Unformatted text preview: 8(.125) = 1.000 Events Heads and Tails are compliments. Compliment of event Head Is Tail Probability of Event A Given the B already occurred P(A/B) If P(A/B) = Prob A given B If P(A/B) = P(A) P(H2/H1) = P(Heads) A and B are independent Events Event is well defined outcome. I=N 1 = ∑ P(Event i)………………. .EQ 4.4 I =1 N Events 0<= P( Event i) <= 1.0 Pg 164...
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This note was uploaded on 06/19/2011 for the course STAT 260 taught by Professor - during the Fall '10 term at Sam Houston State University.

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Oct 15, 2010 - 8(.125) = 1.000 Events Heads and Tails are...

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