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Unformatted text preview: 2. Normality Calculate the pH of 0.0003 N Ca(OH) 2 Remember, normality describes the moles of change per liter of solution, not the moles of a particular compound or ion. [OH] = 0.0003 N = 0.0003 M = 3 x 10-4 M (there are two moles of hydroxide anions per mole of Ca(OH) 2 but only one per mole of charge, or equivalent). - log of 3 x 10-4 = - log 3 + - (log 10-4 ) = -0.477+ 4 = 3.52 pOH = 3.52 pH = 14- pOH = 10.48 IV. ACID-BASE REACTIONS (NEUTRALIZATION) The formation of a salt by the addition of an acid to a base is called neutralization. In a neutralization reaction, we are primarily interested in determining the amount of an acid or base that is present. This is accomplished by adding known amounts of a base or an acid to the solution until an endpoint is reached. This process is called titration. When the endpoint is reached, the following relationship exists:...
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- Spring '08