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Unformatted text preview: by 1 and the reducing agent by 6. The equation then becomes: K 2 Cr 2 O 7 + H 2 SO 4 + 6FeSO 4 Cr 2 (SO 4 ) 3 + 3Fe 2 (SO 4 ) 3 + K 2 SO 4 + H 2 O 4. The coefficients of H 2 SO 4 and H 2 O are still unknown. If we add the number of sulfates (SO 4 ) on each side of the equation, we see that the coefficient for H 2 SO 4 must be 7 and therefore 7 for H 2 O. The balanced equation is: K 2 Cr 2 O 7 + 7H 2 SO 4 + 6FeSO 4 Cr 2 (SO 4 ) 3 + 3Fe 2 (SO 4 ) 3 + K 2 SO 4 + 7H 2 O B. Determination of Equivalent Weights of Oxidizing and Reducing Agents. The equivalent weight of an oxidizing or reducing agent is equal to the molecular weight of that substance divided by the total electron change per formula unit....
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This note was uploaded on 06/21/2011 for the course NRES 201 taught by Professor Olson,k during the Spring '08 term at University of Illinois, Urbana Champaign.
 Spring '08
 Olson,K

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