This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 13 Current sheet, solenoid, vector potential and current loops In the following examples we will calculate the magnetic fields B = μ o H established by some simple current configurations by using the integral form of static Ampere’s law. z J s = ˆ zJ s x y L W B = ˆ yB ( x ) B B ( x ) = μ o J s 2 C As shown in Example 1 mag netic field of a current sheet is independent of distance  x  from the current sheet. Also H changes discontinu ously across the current sheet by an amount J s . Example 1: Consider a uniform surface current density J s = J s ˆ z A/m flowing on x = 0 plane (see figure in the margin) — the current sheet extends infinitely in y and z directions. Determine B and H . Solution: Since the current sheet extends infinitely in y and z directions we expect B to depend only on coordinate x . Also, the field should be the superposition of the fields of an infinite number of current filaments, which suggests, by righthand rule, B = ˆ yB ( x ) , where B ( x ) is an odd function of x . To determine B ( x ) , such that B ( x ) = B ( x ) , we apply Ampere’s law by computing the circulation of B around the rectangular path C shown in the figure in the margin. We expand C B · d l = μ o I C as B ( x ) L + 0 B ( x ) L + 0 = μ o J s L, from which we obtain B ( x ) = μ o J s 2 ⇒ B = ˆ y μ o J s 2 sgn ( x ) and H = ˆ y J s 2 sgn ( x ) . 1 Example 2: Consider a slab of thickness W over W 2 < x < W 2 which extends in finitely in y and z directions and conducts a uniform current density of J = ˆ zJ o A/m 2 . Determine H if the current density is zero outside the slab. Solution: Given the geometric similarities between this problem and Example 1, we postulate that B = ˆ yB ( x ) , where B ( x ) is an odd function of x , that is B ( x ) = B ( x ) . To determine B ( x ) we apply Ampere’s law by computing the circulation of B around the rectangular path C shown in the figure in the margin. For x < W 2 , we expand C B · d l = μ o I C as B ( x ) L + 0 B ( x ) L + 0 = μ o J o 2 xL ⇒ B ( x ) = μ o J o x. For x ≥ W 2 , the expansion gives B ( x ) L + 0 B ( x ) L + 0 = μ o J o WL ⇒ B ( x ) = μ o J o W 2 ....
View
Full Document
 Spring '08
 Kim
 Magnetic Field, current density, Ampère’s law, Current sheet, dr dφ

Click to edit the document details