hwk08_s07 - penalty if not stapled Name Section Score...

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Name: Section: Score: Homework Set 8 Due Wednesday, March 14, 2007 at 3pm Problem 8.0 Do Week #8 Mallard quizzes due 3 pm Tuesday. Problem 8.1 A sequential circuit has two inputs (X and Y) and one output (Z). The circuit is implemented using two D flip-flops A and B (with inputs D A and D B , and outputs Q A and Q B , respectively). The following Boolean equations describe the combinational logic that is used: D A = X'Q A + XY D B = X'Q A +XQ B Z = XQ B a. Draw the circuit. penalty if not stapled
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Problem 8.1 (continued) b. Give the next-state table, including columns for current state, inputs, output, D flip-flop inputs, and next state. c. Draw the state diagram. Note : this design has two inputs; therefore, when labeling arrows follow the convention XY/Z .
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Problem 8.2 In this problem you will implement a sequential circuit which "recognizes" all occurrences of the following sequences: 1100 and 1001. The output is 1 precisely when the last bit of either input sequence is read. Sample input:
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hwk08_s07 - penalty if not stapled Name Section Score...

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