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81204hw12Sol

# 81204hw12Sol - Zzztayloe Rex – Homework 12 – Heinz –...

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Unformatted text preview: Zzztayloe, Rex – Homework 12 – Heinz – 81204 – Nov 04, 2004 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points At a maximum level of loudness, the power output of a 75-piece orchestra radiated as sound is 67.8 W. What is the intensity of these sound waves to a listener who is sitting 20.8 m from the orchestra? Correct answer: 0 . 0124708 W / m 2 . Explanation: Basic Concept: intensity = P 4 πr 2 Given: P = 67 . 8 W r = 20 . 8 m Solution: intensity = 67 . 8 W 4 π (20 . 8 m) 2 = 0 . 0124708 W / m 2 002 (part 1 of 1) 10 points A stereo speaker represented by P in the fig- ure emits sound waves with a power output of 95.57 W. P x 9 . 36 m What is the intensity of the sound waves at point x , 9.36 m away? Correct answer: 0 . 0868081 W / m 2 . Explanation: Basic Concept: intensity = P 4 πr 2 Given: P = 95 . 57 W r = 9 . 36 m Solution: intensity = 95 . 57 W 4 π (9 . 36 m) 2 = 0 . 0868081 W / m 2 003 (part 1 of 2) 5 points Transverse waves with a speed of 45 . 9 m / s are to be produced on a stretched string. A 6 . 52 m length of string with a total mass of . 0524 kg is used. What is the required tension in the string? Correct answer: 16 . 932 N. Explanation: Let : m = 0 . 0524 kg , ‘ = 6 . 52 m , and v = 45 . 9 m / s . The linear density is μ = m ‘ , so v = s F 1 μ F 1 = μv 2 = m ‘ v 2 = (0 . 0524 kg) (6 . 52 m) · (45 . 9 m / s) 2 = 16 . 932 N . 004 (part 2 of 2) 5 points Find the wave speed in the string if the tension is 16 N....
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81204hw12Sol - Zzztayloe Rex – Homework 12 – Heinz –...

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