4.2 Notes

# 4.2 Notes - Step 2 Choose a pair of equations and add them...

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4.2 Solving Systems of Equations in Three Variables Goal:  Solve three equations with three unknowns The solution of a linear equation in three variables is an  ordered triple (x, y, z) that makes the equation true. HW problem #1: Which equations have (-1, 3, 1) as a solution? a) x + y + z = 3 b) –x + y + z = 5 c) –x + y + 2z = 0 d) x + 2y – 3z = 2 We can use elimination or substitution to solve a system of three equations, just like we  did with a system of two equations.

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Solving a System of Three Equations using Elimination: Step 1: Write each equation in standard form Ax + By+ Cz = D
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Unformatted text preview: Step 2: Choose a pair of equations and add them to eliminate a variable. Step 3: Choose another pair of equations and add to eliminate the same variable as in step 2. Step 4: Solve the resulting system of two equations for both variables. Step 5: Substitute the values of the two known variables into any of the original equations and solve for the third variable. HW problem #5: x – y + z = -4 3x + 2y – z = 5-2x + 3y – z = 15 Homework: p. 233 #1-16...
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## This note was uploaded on 05/16/2011 for the course MTH 201 taught by Professor Suh during the Fall '08 term at Grand Valley State.

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4.2 Notes - Step 2 Choose a pair of equations and add them...

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