{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

4.2 Notes

# 4.2 Notes - Step 2 Choose a pair of equations and add them...

This preview shows pages 1–2. Sign up to view the full content.

4.2 Solving Systems of Equations in Three Variables Goal:  Solve three equations with three unknowns The solution of a linear equation in three variables is an  ordered triple (x, y, z) that makes the equation true. HW problem #1: Which equations have (-1, 3, 1) as a solution? a) x + y + z = 3 b) –x + y + z = 5 c) –x + y + 2z = 0 d) x + 2y – 3z = 2 We can use elimination or substitution to solve a system of three equations, just like we  did with a system of two equations.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Solving a System of Three Equations using Elimination: Step 1: Write each equation in standard form Ax + By+ Cz = D
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Step 2: Choose a pair of equations and add them to eliminate a variable. Step 3: Choose another pair of equations and add to eliminate the same variable as in step 2. Step 4: Solve the resulting system of two equations for both variables. Step 5: Substitute the values of the two known variables into any of the original equations and solve for the third variable. HW problem #5: x – y + z = -4 3x + 2y – z = 5-2x + 3y – z = 15 Homework: p. 233 #1-16...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern