Molecular Weight by Freezing Point Depression

Molecular Weight by Freezing Point Depression - Molecular...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Molecular Weight by Freezing Point Depression David Mulkey 3/30/2011 Chemistry 118 Section M3 Group Members: Stephan Real and Justin Pollock
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
1. Molecular Weight of the Unknown: a. The unknown used in the experiment was unknown number 709. In the experiment the molecular weight for the unknown in the first trial was 136.766, and the molecular weight for the unknown in the second trial was 135.366. The standard deviation for the unknown was 136.066 + or - .9901. The results from the two trials showed that the molecular weight for the unknown was very precise according to the standard deviation. The trials also showed that by using the class average for trial one (183.817) and the class average for trial two (171.540) as the accepted values the percent error for trial one in the experiment is 21.09%, and the percent error for trial two in the experiment is 25.6%. For this reason, the results were not as accurate according to the class averages. 2. Determination of the K f of Water: a. In order to find the K f , the freezing point constant, of water the following equation must be used: K f = ∆T f / i*m where ∆T
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 3

Molecular Weight by Freezing Point Depression - Molecular...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online