L567 lecture 7 - L567 Lecture 7 During the previous lecture...

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L567 Lecture 7 During the previous lecture we began thinking about Game Theory. We were thinking in terms of two strategies, A and B . One way to organize the information is to put it into a “payoff matrix When interacting with “Payoff” to A B A E( A , A ) E( A , B ) B E( B , A ) E( B , B ) Where, for example, E( A , A ) gives the expected payoff to A when interacting with A . We could rewrite the matrix to read When interacting with “Payoff” to A B A a b B c d Note that 1) if a>c, then A is and ESS 2) if d>b, then B is and ESS 3) Either A or B could be an ESS. The outcome of selection would then depend on initial conditions. Hence Natural selection does not necessarily result in the “best” strategy winning. Show this graphically. In addition, no claim is made that either A or B represent an optimal strategy. 1
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L567 Lecture 7 4) if neither A nor B is an ESS, then selection is frequency- dependent. Both strategies will increase when rare under the action of natural selection, leading to a stable polymorphism.
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This note was uploaded on 07/01/2011 for the course L 567 taught by Professor Curtis during the Fall '10 term at Indiana State University .

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L567 lecture 7 - L567 Lecture 7 During the previous lecture...

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