solution_8

# solution_8 - ouseph(jao888 HW08 tsoi(92940 This print-out...

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1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 of 2) 10.0 points You weigh 250 lb. How much would you weigh iF you were standing on a mountain 200 km tall (equiva- lent to standing still at about the altitude oF a space shuttle orbit)? The gravitational con- stant is 6 . 67 × 10 11 N · m 2 / kg 2 , the radius oF the Earth is 6 . 4 × 10 6 m, the mass oF the Earth is 6 × 10 24 kg, and the acceleration due to gravity is 9 . 8 m / s 2 . 4.45 N = 1 lb. Correct answer: 1042 . 95 N. Explanation: Let : W = 250 lb , h orbit = 200 km = 2 × 10 5 m , r E = 6 . 4 × 10 6 m , and G = 6 . 67 × 10 11 N · m 2 / kg 2 . The gravitational acceleration at an alti- tude oF 200 km is g = GM E r 2 = GM E ( r E + h orbit ) 2 = (6 . 67 × 10 11 N · m 2 / kg 2 ) (6 × 10 24 kg) (6 . 4 × 10 6 m + 2 × 10 5 m) 2 = 9 . 18733 m / s 2 . Your weight is W = 250 lb × 4 . 45 N lb = 1112 . 5 N , so your mass is m = W g = 1112 . 5 N 9 . 8 m / s 2 = 113 . 52 kg . At an altitude oF 200 km, your weight would be W = mg = (113 . 52 kg) (9 . 18733 m / s 2 ) = 1042 . 95 N . 002 (part 2 of 2) 10.0 points How much does this di±er From your weight on the surFace oF the Earth? Correct answer: 15 . 6294 lb. Explanation: W -W = 1112 . 5 N - 1042 . 95 N = 69 . 5508 N × 1 lb 4 . 45 N = 15 . 6294 lb , which would be easily detected on a bathroom scale. 003 10.0 points Three masses are arranged in the ( x, y ) plane as shown. 4 kg 4 kg 5 kg y (m) 1 3 5 7 9 x (m) 1 3 5 7 9 What is the magnitude oF the resulting Force on the 4 kg mass at the origin? The value oF the universal gravitational constant is 6 . 6726 × 10 11 N · m 2 / kg 2 . Correct answer: 8 . 62063 × 10 11 N. Explanation:

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## This note was uploaded on 07/09/2011 for the course PHY 302 taught by Professor Staff during the Summer '08 term at University of Texas.

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solution_8 - ouseph(jao888 HW08 tsoi(92940 This print-out...

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