Unformatted text preview: d[ES] ╪ = k for [E][S] (Appearance of T.S.) dt Now set appearance of [ES] ╪ equal to the disappearance of [ES] ╪ … (Steadystate assumption) d[ES] ╪ =d[ES] ╪ ; k for [E][S] = k B T/h[E][S] e∆ G ╪ /RT (Cancel [E][S] terms) dt dt k for = k B T/h e∆ G ╪ /RT (Kinetic k for related to thermodynamic ∆ G ╪ ) So, from the equation derived if ∆ G ╪ is large, then the k for will be low and the overall rate is slow. And if the ∆ G ╪ is small, then the k for will be high and the overall rate is fast. There is an inverse relationship between ∆ G ╪ and k for due to the e∆ G ╪ term....
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 Summer '11
 Stern
 Biochemistry, Thermodynamics, Catalysis, Chemical reaction, 23 J, State Theoryenzymatic reactions

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