key-eng-fall07-q8059x05

key-eng-fall07-q8059x05 - CHEM 2045C: Quiz 5 Show your work...

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CHEM 2045C: Quiz 5 Eng Q8059x05 Show your work for full credit Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 7.50 g of sulfuric acid and 7.50 g of lead (II) acetate are mixed, and 6.03 g of lead (II) sulfate forms, we will determine the percent yield. If 2.43 g of sulfuric acid and 2.43 g of lead (II) acetate are mixed, and 1.97 g of lead (II) sulfate forms, we will determine the percent yield. If 4.38 g of sulfuric acid and 4.38 g of lead (II) acetate are mixed, and 3.86 g of lead (II) sulfate forms, we will determine the percent yield. i. (3 pts) Write the balanced reaction. Do not forget the states. H 2 SO 4 (aq) + Pb(C 2 H 3 O 2 ) 2 (aq) PbSO 4 (s) + 2 HC 2 H 3 O 2 (aq) ii. (1 pt) Write the total ionic equation. Do not forget the states. 2 H + (aq) + SO 4 2- (aq) + Pb 2+ (aq) + 2 C 2 H 3 O 2 - (aq) PbSO 4 (s) + 2 HC 2 H 3 O 2 (aq) Note: acetic acid is a weak electrolyte; therefore, it is NOT written in the total ionic equation. iii. (1 pt)
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This note was uploaded on 07/10/2011 for the course CHM 2045 taught by Professor Eng during the Fall '10 term at UNF.

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key-eng-fall07-q8059x05 - CHEM 2045C: Quiz 5 Show your work...

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