{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

MIE376 Lec 12 DP.page12

# MIE376 Lec 12 DP.page12 - 3(4 = Min[17 16.5 15 16 17]= 15...

This preview shows page 1. Sign up to view the full content.

MIE 376 Mathematical Programming 12 Stage 2 (Demand = 3) f 2 (0) = Min [3 + 3*1 + f 3 (0), 3 + 4*1 + f 3 (1), 3 + 5*1 + f 3 (2)] = Min [18, 17.5, 16]= 16 and x* 2 (0) = 5 f 2 (1) = Min [3 + 2*1 + 0.5 + f 3 (0), 3 + 3*1 + 0.5 + f 3 (1), 3 + 4*1 + 0.5 + f 3 (2), 3 + 5*1+ 0.5 + f 3 (3)]= Min [17.5, 17, 15.5, 16.5]= 15.5 and x* 2 (1) = 4 f 2 (2) = Min [3 + 1*1 + 2*0.5 + f 3 (0), 3 + 2*1 + 2*0.5 + f 3 (1), 3 + 3*1 + 2*0.5 + f 3 (2), 3 + 4*1+ 2*0.5 + f 3 (3), 3+5*1+2*0.5 + f
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3 (4)] = Min [17, 16.5, 15, 16, 17]= 15 and x* 2 (2) = 3 ± f 2 (3) = Min [3*0.5 + f 3 (0), 3 + 1*1 + 3*0.5 + f 3 (1), 3 + 2*1 + 3*0.5 + f 3 (2), 3 + 3*1+ 3*0.5 + f 3 (3)] = Min [13.5, 16, 14.5, 15.5]=13.5 and x* 2 (3) = 0 ± f 2 (4) = Min [4*0.5 + f 3 (1), 3 + 1*1 + 4*0.5 + f 3 (2), 3 + 2*1 + 4*0.5 + f 3 (3), 3 + 3*1 +4*0.5 + f 3 (4)]= Min [12.5, 14, 15, 16] = 12.5 and x* 2 (4) = 0...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online