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Unformatted text preview: p + z*sqrt(p(1-p)/N) = 0.013139 + 1.96*sqrt(0.013139*0.986861/86991) = 0.01390 (0.01238, 0.01390) (b) Why is the normality assumption not a problem, despite the very small value of p ? (Data are from Flying 120, no. 11 [November 1993], p. 31.) N is such a large number pn and qn are both greater than 5, it is a normality assumption. np = 1,143 > 5 n(1-p) = 85848 > 5...
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This note was uploaded on 06/25/2011 for the course RES 341 taught by Professor Hermis during the Spring '10 term at University of Phoenix.
- Spring '10