hw3_sol - 134.8 191*“: 4|] 3 :0 'll-‘g—lli v.2 1,2 3...

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Unformatted text preview: 134.8 191*“: 4|] 3 :0 'll-‘g—lli v.2 1,2 3 +fi+m+l—D Solving. m = 120 V; 113 = 96 ‘9’ CHECK: (120)? 40 2360“ P409 2 = 72 w 3 Pan: _(9fi)2_ h F Imn— SD -1102“ _ (96)fl _ I Putin — m _ 75.3 15. m = —c6){120) = 420 w PIA = (1)(96} = 96 w Zpahs : 350 + "r2 +1152 + 76.8 + 95 : m w 2de = ":20 w (CHECKS) P 4.13 [a] 50 an 100 + + 12'3" ul am! v: 3m; 333'" 1'] — 128 in v1 — 1.12 ._ = {1 .5 +61] 4 'U2 — #1 1‘2 1'2 — 320 _ : I] .1 + 30 + 10 In standard farm, .(1 i. l) . _l) _ £3. 1" 5+fifl+4 "H4 4 ‘ 5 ..(__1.) (1.1. i) _ fl "" 4 “‘2 4+80+10 — 10 Solving. m = 162 1": 2:2 = 200 V £33M:_6_3A 5 aplgcam I, _162w—2U{}_ C— d — __2m_ 1, Id—S—fl—2.0A , EDD — 32-0 to —. T —r A [b] piggy : —(l23}(—fi.8} : 870.4 W (abs) 1mm: : {320H—12} : —3340 W (dis-r) Therefore, the. total puwer dam'eluped is 3340 W. —9_5 A P 4.1?[511 w25+ fl+ i+ 1'1 h 1'2 20' so 21?.']“16T*fl+nifl:4nm 40 160 II] “2 _ I" + “2 + “2— mi‘ * In 16' +44» 1680' — 0 ID 20 8 _ 5” 1'1 t9 “1 — , U _ m = 17““ an m + (mt-g —16l}.-.¢ = D Sulving, m = 352 V: 113 = 212 V; i; = 2.2 A; mm = w = 3,4 A pain-n : 54(2.2}(3-4} : 323.32 mains} pm = —25{352} = 4.300 wmeu . pm = 3qu w {3232}2 (3122.2)2 {352 — 212?2 (212}2 b 1 = .— HZP‘b“ 40+16fi+ 10 +20 +(3.4)=?(8) + 628.32 = 3300 w ZPdQVZZPabEZSSUflw P 4.24 The two node vnltage equations. are: 111 — EU "111 111 — 11:1 31] + E + 41} = D L'g—t'] _ r i 112—50 _ 40 [1111+ 200 + 800 — 0 Place these equations in standard form: . (1+i+i) + .(4) _ e "1 311 511 41} "2 111 " 30 ( 1 ) ( 1 1 l ) _ U Tr 51] *4 'm + *9 m+m+m — “’+31]1J Solving, 11] = 34 1."; 113 = a3.2 11'. Thus. ea 2 e2 — 50 = 53.2 — SD = 3.2 V. POWER CHECK: 1'5, = {50 — 3:1),130 +150 — 53.2)/SDD = 19-6111 11 P511? = —(50)({].196) = —Q.S W pane = {50 — 3419/80 : 3.2 W 13311011 = {511 — 53.2}21301] = 12.3 111 W p.113; = {53.2 —~ 3412,31in = 9.215 1W pang = 34?,150 = 23.12 w P211011 = 5329/2110 = 14.1512 w mm = —(53.2}(0.75} : —39.9 w 2112.11; = 3.2 + 11123 +9216 4—23.12 +14.1512 = 49.? W 2 2:11:19] 2 9.8 + 39.9 : 49.? P 4.27 Place 5111, inside a. supernede and use the lewer node as a reference. Then 1.13 — 15 +195 + 1.113 — 5131, + 1.15 -—- 5111:. _ U 10 ‘2 20 41] _ 12113 :60; 11$ 2 5 V 1.", 2 11,3 - 513 = --1[5) = —20 V ‘ ' + supernnda Nude Equations: e; 131-20 L's-1'2 If: . . .. E T T E 3.1251fiwfl Constraint Equations: I}; = 2D - 1:2 “1 - = in, = we} Solving, m = —2U25 V1 1.1: = II] V: v: = —'29 V Let i9 be the current delivered by the 2L} 1' source, then . _2n—{ee.25} 20-10 .9 2 = sum :1 pg {delivered} = 2{]{3[J.125-} = 502.5 w P 5.34 [a] 233 — 115 = Til — 1:2 — 223 u = —1:'I —— 1m2 — 3:3 115 — 4.52 = -3:'. - 31': -— lflfg Snlving. I; = 4.4 :1: 2'2 = -1fl.fi A; 155 = -35.3 :1 pm = «23221 = -1012 551351} pm = 11591 -— 13} = 4733 1.21555} Jim] = 215553 = 45.925 15-1351} and... = 17.253 w [1:] mm = {mfijflém = 52.1. 15 w F1:1={15}2{1}= 225 W p351 = {25.2}1{3} = 2553.32 15‘ pm = {51.23122} = 3324.55 11' p49 = {-1.4}24} = 73.54 15' 559 = (35.3335) = 5271.2 15' Zn...“ = 4733 - 524.15 - 225 — 2352.32 -— 3322.53 --TT.41 -- 5771.2 = H.943 ‘s‘f P 4.39 65:1: 3m1 am: —15:', “Min = —1ml — 5mg — 5m, 0 = —15£1— 5m: + 9mg, g=g—g Solfing, i; = 42 A: 1'2 = 2.- A i; = 22 A; id. = a A 2m, = mu 1.: m; _ anon; _ —1DU{27} _ —2?uu u: -_ pith {date-10pm!) = 2mm 11’ CHECK: paw = -$0{42} = -2T,?‘2fl I? {flew} 272720 + 2739 = SHAH] W (427:2{5} — {2mm — mums} — {a}?<an}— {IEFUH} SUE-12E] W MM 31:23 :' 5! II II II P 4.45 Mash equations: 1m; - 4&1 = n -455 -- 241'1-h ESL; = 4m SoIving. i1 = 15 A: 1‘; =16 A um = if; -- 5.5:; = 7.5{15} = 120 1--' M = —m:..-m = —{20}{120} = 42400 w {dei} p415; = 5.53ml = {fi.5}{1fi}{15} = 1.55:: 1*: {subs} Thereinre? the dependent murae is dEx-elflpmg 24GB W, all {it-1191' 912111911125 are absorbmg pass-"en and the tntal paw-er develaped is thus 2400 W. CHECK: pm 4153:9111}: 255 11' p5“ = {an — 1s}={.5} = 30 w Pm = {1}?er = J. w pm = {20 — 15}3{2n} = sun w 2pm = 1550 — 255 + an — 4 —— 501:] = 2.1m] W {CHECKS} 1’ 21.51 [a] 135.1 mm = 35:1 — 251': — am; I] = 451': * 351i: * 150$; {supErmeS-h) 1:3 —i1 = — 50111115: i1 = «1.5 .11: 1'2 = 5.? :1: i3 = [1.97 A i1=f2= 5.7.31: fl): {'1 =4.5 :1 ic=i3= [1.97 :51; id=il—ig=—l.1 A in =1} —i3 =34fi3 A [b] 102‘; — 1:0 450*; —- £1}: [1 “a = —57— 2?.5 = —S—L5 V pm: = -:.-a{4.3id} = -{—34.5){4.3}{-1.1} = 4399.535 firmer} pmv = -2DD{4.6} = -92[} Wafdev} [Pm = 1319.535 11‘ [Hm = {5.7.5910— {1.1}={25} - {0.971131% — {4.5}? {10‘— {3.632(50} = 13131535 1T 2PM. = Zpfih =1319J335 “‘- P 1.59 [3] Apply murcfl trflflfiffil‘mfltiflns tr} bath current EDuI'EEE tn get --.’5.:1-- £1.31 I. _ IIHI + 2mm +1l1l1fl in [b] D Bum The nflde l'flltflgé Equfltiflna; ['1 1'1 m- 1'2 F: T": — T'L Place them:- Equminns in standard farm: 1 I l + _. _ _. _ = r) 3 " (2.110 2300) "’( 23ml) ' x m" ‘ l I ( l l _3 "l 23cm) "2 man 2300] '15 X m Solving! r); — 2.7 1—: pa; — [1.4 T 1'2 — 1'1 1 = —l m '1 " 231m ‘ F 4.52 [a] First rEmm-‘E the 1B O and 26D if} reaiutflru: Ecxt use a murcc trflflai'crrulutiflu tcr ccun'crt the 1 A current murce uud JIM! rcsistur: 2511], r . [1]] Return tn the nrigiuu] circuit with ca = ~1flfl Y: may = —{52U}{3.fi} = 4372 it Therefore, the Bit] E" source is dm'elflping 1872 W. In] :11 = —-:':2[i -- 1.5{4 -- 25D -- E} = -ii]:1 E" t-g = u; —1{15}= —1e4 — 15 = —120 t‘ pm = mtg-121:1} = -12[i t-t' Iherefere the 1 :1 seurce is developing 12D W. [d1 2pm = 18T2 — 12111 = 1992 w ‘ 2 "'I] 2 Emits = {lilailfii * fl - {Ch—U} * “1.e}2{250}=1992 tt‘ 4D 25D Zpdlsn = P 4.64 First we make the nbsert'etien that the li] 111.51. current eeurce end the li] k5] reeieter 1will have 1m influence {in the behevlflr {if the circuit 1with rEepeet t0 the terminals eh felines because they are in parallel with an ideal mitage eeurce. Hence our circuit can be simplified to a 15:11 3w 6 fl! Skfi flierefnre the Net-ten equivalent is a {5 3.15m 134.55 [a] Open circuit: t'g-Q Pg ————1.S=[} ‘2” T 12:35 ‘5 ED . rm = in; =3U ‘1 Short circuit: im= l.3-—-L‘|.3 =15;- A 3|] HTIl = —-_- = QUE] 1..) [h] P 4.55 11.7 = I'J'Th — 1331311 Solving the abm'e equatinna far Em and R111 yields [-111 = T. 31‘}; = 5” mi? IN = 252 A. :1... = an mfl ...
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hw3_sol - 134.8 191*“: 4|] 3 :0 'll-‘g—lli v.2 1,2 3...

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