hw5_sol - (LT! ('41 «00 = —(0.5 X 1040103000) 2 —5 V...

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Unformatted text preview: (LT! ('41 «00 = —(0.5 X 1040103000) 2 —5 V 'L-‘O —5 $0 2 5000 Z 500 : AIDA vb — Iva + _Ub — v0 : 0, therefore i=0 : 60b — 5-0,, 20,000 100,000 [a] 'L-‘a : 4 V, ob : U V, no : —15 V (sat) [b] 0;, : 2 V, vb : 0 V, '00 : —10 V ea : 2 V, ob : 1 V, no : —4 V 1?0 10-3 [a] :22 : L : T5;1.,-'\ 2000 01 = —40 X 103;:2 = —3\.--' t1 t1 151— to 0 [ ] 20,000 40,000 50,000 no : 4.?51-‘1 : —14.25 V [(1] 2'2 : T5 iii-X, {front part 2: [d] to = .— 11“ — 131—”) = r05 ,0. A 20000 00,000 [a] Replace the combination of My, 1.6kQ, and the 6.416.? resistors with its 'l'héx-enin equivalent. w» o ’l .6 k D ’l .28 k0 0.25U 6.4kQ 0.2V l i 4 —'12 — 0-50] Then t: :'—’0.20\I ° 1.28 i ’ .-'\.t saturation no : —-5 \-"':_ therefore 12—050 ,09\_ ,_ , _04 (1,28 >L._,_ 0, or (1—. Thus for 0 a 3’. 0.40 the operational amplifier will not saturate. [b] when 0' = 0-271 vo = W020) = _4 v 'U 1.! A] —O 0 'Io : 0 SO 10 + 25.6 H I 1:10 U0 4 4 Hr. Iv 30 : 10 25-6 : 10 : 256 mA : 30620 #A P 5.12 [a] This circuit is an example of an inverting summing amplifier. 220 220 220 [b] no = ——a — _ , 0h — —a = —.5 — 12 — 11 = —0 44 2:10 80 [e] no : —6 — 80h : :th Uh : —0.5 \-"' when no :10 \..-"1. U}; I 2 when no : _ —0.-5 V 3 Nb 5 2 \s' P 5.1? [a] This circuit is an example of the non-inverting amplifier. [b] L'se voltage division to calculate up: 10,000 as "F 2 10,000 — 30:0001’5 _ 4 Write a KCL equation at on 2 up = L‘s/ill L‘s/i]: [ls/.11— L10 — 0 4000 28,000 _ Solving so = Tits/4 — 1.15/4 2 21.15 [c] 2'05 : so Us : 4 \-"' 24.15 = —12 so us : —6 \-"' Thus, —6 \s’ g as g 4 \..-'_ P 5.20 [a] This circuit is an example of a non-inverting summing amplifier. [b] ‘Write a KCL equation at up and solve for up in terms of L‘s: up — Us up — 6 _ 15,000 _ 30,000 _ 20p — 21:15 — up — 6 = 0 so up : Ens/3 — 2 Now write a KCL equation at on and solve for 00: an an — '00 20,000 _ 00,000 : so no : 40,, Since we assume the op amp is ideal, an : up. Thus, 00 = 4(205/3 — 2} = 8115/3 — 8 [c] 805 / 3 — 8 : 16 so Us : 3 \-"' Sits/3 - 8 = —12 so as = 4,5 Thus, —?.-5 \s' g as S 3 \s’. P [a] Up}; Na _ Up 1;} Nb _ Up}; NC _ E}; Z 0 a a c g in _ RbRcRg?‘ RaRfi-‘RQ in RaRbR-gp "p — T — T xb — T «'(r where n : macs, — Bases, — Rama, — name, an L1,, — no Rs Rf :0 01‘ r _ 4,129,124,121. 1” 4894241421? ,0 _ »'b R’RgRbR: RC _ 1') _ I) _ Rh 0 R. 3 _, Ra 3 Rb {J U = {21"133'{3}-{1}{13}{3} 443342341 >< 10g _ 22.5 X 109 _ 13.5 X 109 1‘1? : : 1.7 0 X 109 J Rf- 1? : _ _ J Rs Rf- — :14 Rs 141-4143415000}: 210 M} [b] 1:0 2 010.5} — 312.5). — 4(1). 2 14 14.5 = = _ = 0.907 1 1p 10 1 . _ 05—000? _ 466 67 x 3a— 1000 —— . 1,11..- — 0.007 4b = ; = 200021114 2000 1'“: fl = 22.221144 ' 1500 0.00? ' = — = 322.22 ’9‘ 3000 ‘” , 0.00? is = 64.44115": 2 15,000 : 1.5,000 1700 \ Up I J 3' Z _3 Z “a 9000 —3+ 18 —3— 1:0 : 0 1600 Rf 110 : 0.0093?5Rf — 3 1:0 : 9 \5; Hf- : 1280 .Q 1‘0 = —9 \5; 1%- = —6—10§Z But Hf 3 01 Hi- : 1.2816? ._1.3—10 : 1 111:1 ’71 _ .3000 :2 +11 + O : 1011131; 3'2 = 91114’\ 1:02 2 10 + {1003.193- >< 10-3 = 13.6 \.-' 1.1: 1'3 +11: 1.1711111 1:01 =15 * 1110.51 2 1.5.8.3 \.-' 5M1 :' = Cl till] 3' = SOL-‘5. 05:35:11}: 3' = US—SUE‘L ifitilflma :' = Cl iflma-{a‘ rh' _5 u , _ =IF=EUXID :U =1‘v Ugtflamb r. r220 ><1L1‘a —5r:I =—1‘~.-’ 5 @31le r: = [J “a: CI r: = 1V Il-cf. t if. 511-5 r: = -1‘I." iétélflfls r: = Cl 10111.5. {t p=--:' p = U t-(U p = {Earl-{1:} = 53:11: El < t a: 5 ms, 11 = {0.5 — ENE-11'- : 50f — 0.511." 5 { f 4:: 1 m: p = [J 1UIILS-fiif r.r' — El trig t :1! t u- = if {sum} rim = 5r]— : 25:? .1 a a: m: .3 H15 .11] 2 u t .- -\. u- = {F 1.5er —E|.5}rfrr 4.52.5 x m 5 .JUJJUE I t I = 2-532 — 0.5.1: $0.825 X 30—5 mm = E-SfE—U.5t-2.5><1E]'3.T -3-::f-::1Elma r.r' — El lflIl'u-Lir‘. P 5.5 [a] 1-31} = 11-me12 = 11.111 11' . r7: = ‘10-000.4=.e_"”=””m — 111.000.1213-4WU‘ 1:: —:21111.111_e-i““”“* — anughedwfl‘mtxr {JD} 2 — = '-. SGh'ing: A; = 0.1 and .512 = —0.:|E Thus... 3-1 ={1nme-imflr— E0edm=flflm} 11111 13 n F = _2:|e—l{|:11|flfu_ Else-fliufluflf 1k?“ El [11'] 1": 0 1.111911 1003—”Jmm = Egg—“WWW Therefc-re 6mm” = 0.0 51:- 1‘. = —}?.0311::'. which 151101 possible! 1: = 0 11-11911 20e¥m=uum = {lfiedmmm Therefc-re E33111111111 = 2,1 5.3. f: 2918115 Thus the pmrer is zero at t = 20.13115. 1000 t 20 . 11 P 5.9 [a] — 5103111 250:: r1711: --10 an... — «:05 250.1: E —2500 TD “0 ~10 0 104203 2501f 1'1 E “I: II 171' = {-505.111 2501:11001205 2501‘:- — 500 5111 2501? 1:05. 2501‘. p = —2505i115001‘“' 1 . r:- = 310.52 1, .. a = 3120 X 10 11:01:05 2:100.- = 10001205.2 25101111.] 11- = {-300 -- 500cm. 500t3-11'1J 511 3:1 Mjsflrhing power: Dfllh'cring pmver: '27 E: 9‘ :1 1.7119; [11: #1: 271115 I3: 1’: 9‘ fl E71115 -l..— E: 9‘ E 671115 3.100 X 10—3 ixlffl 1:80x1031 0515505 P 0.1-1 [3.] 1: 1: 100 ><1'3 0 g 13 000.1- BUUXIETE 1 .2 _ In: - _ I“ 2 .. I —30Xm_fii‘ Do 101‘ 00 U;!.:~___f_'_]fllrjn 5x111“! Lama-4' [ 8x 10=101mf 0001 q = .0 . fixifl"! t? 5x104 2 S x101? $0.0{10 >< Hill—fl} u 0 = ~1><10*{25 >< 10-91mm 10-6 = 511C fl fixlfl‘“ I {j 211x111“! [13] 1-:1x 10 f 0 x 101:0“ .1 x 10 f 0.101: . 0 . 5xlfl‘* HflxHJ-E , ‘ +0 x 10% 11011—00201 . 20x10“! ' flTE 5x104 'i'flxlfl‘“ 3:? 30x10“ 30x10“ 2 d X llflfj [a x10"? -D.~i1: ~10“? —D.507 u 0 fixlfl'“! u auxin-E Emma-m =-1><103}1 “011125 x10‘”}-— 0.0-;10 x 10-3} 4000:1100 >< 10-12100 x 10-12} — 0.5{10 x 10-33.] = 101: 19:30 11:5} = 18 ‘0" [c] r.--:;0001-.j:- = .1 x 10010-6 J 0 x 10-6 w 5000:0500 x 10-” — 100 x 10-”;- — 0.030 X 10—6)} = 101-? l . l , .. .- u- = 300.! = 310.05 >c 10-5010,:g = 1015 0.1 1 135.10 [a] r: 500x104 I I [H 00 x 10-ie-NW01— 00 40001 500x10“ 3 —0r: 100 103 X —0000 fl = 00{1— 3-1} — 20 =11.011-' m = it}??? = é-i:U.-3}-i:1|:|_fi}{l1.51}?! = 33311.] r.-'-' 3-0} = 5 — 1. ] = " h ; _ 0 01 301 mix} = E10.0 x 104000;? = 0000.1 J.- 138.10 [a] i=Cf—;=0._ mu I. T ur r.‘ F . . , _ [h] i: c .1 x lu—fi‘.—_1nm — .1Dfi—m”*-;3ms 1mm: a-sinl000fll E = dt = :1 X 104 '_—.:1L‘I{—2r:u:|:1j.~e-?”“”*{3 :95 mm]: — .':'.in1|'.:|00f:1 —-'10-:1000:.-3_Wm-;:—3311:1000t+ C05 mum}! 0.322-W”“f-{3cos mm: a 5111 1003:} — 015-9353111000: — +205 1:100:3- 0.05'Eufl'flfim 1mm: — 51111000tjfi. :3 r3 [1:] 110. T:{0'} = —20 15-" r..-{U+j:- = 100—10-31-{3} = —2EI 1.? [:1] 33951 5-:0_:- =0 3'5. 193'}: 0.3 a [E] = 100 V r: = éCrrE = X 10_fi:I--i:100}2 = 20 111.] P 6.20 BONED =12H sun-{a _12;.=15H SUM-:14 -15} = EEH mum L10} = ECH Lab =3m10=15H P 5.23 [a] 55-31:;- = 4.310} — £2410} = r3 — 1 = 5A ['3] :i.u + —1E|l:|l: Leq=flH 20003 R! 1 t W e—iflflr " .t' = —— 20005:“ I rim w 5 = —500 m 5 a El. 11 —100 a = Ede—“1‘” — 1} -— 5 = Sue—WA. t3 0 L‘E = 3.2-i—Sflflr3—iflwl- = —ifiUUe—i“'“\' 12': — [a -- r.'r_- — —IEUL‘Ir:—E”"'i -- BUGLE—54"" = 4003—1“? 3 f . i; = —[ dune-“NI rim — r3 1. u = —-ile"‘m‘ «- -1— 6 .PI:_ = —'1E_:'£m — Pia U l t . [d] :3 = —[ mug-W arm *3 d. u = —e—””*+2.-"L “EU 1 1, i i i , i [e] M k0- = E3 kB 3 * Emit? —— —\3 235;? = 60 .I 3» a ,. if] “He! = 3-1-1 ‘5} = QUIT [g] nmppad = BU — 53:10] 1'. hwyfl I. wrong I. .l 01' run-appea- = Egg-W- m akin”;- * 1|] .1 $119ch ME i=i~i=i fl=flfl Emir” luv i + 1 1 i =_..__..._=_ =9. {*5 a 2L] 1 2 [5 “M SHF 5.0—“- + 5v— _ luv‘ZULLF J _3|]1u"+ bO—H' QaF Equixalant capacitance is 211.1: with an initial voltage drop of +25 V. P 6.34 F = {5;:-{e-2"““*'_—aunusin 400m Emacs}: «100mg m-ganue-Wfi-Em 4:11er m 5111-10009?“ 2 e‘mm{—SU.Dflflsi11~iflflflt}‘v' fir}; . , \. . . I -'+ '- = {1J:-_5111{D}_i = E] arr." 10>: 10—3 Ila , _ , LEI-F} = U .50 ?_r2-Llj+} = I] [rt-{0+} = gain-{0+} w mm} = 40-30} = u = 400V 1 f , t P 5.35 r: : —— 1'5 —Lfid1|fl2 firm _ [ DIE-J 4mm: firm) _ 50 UfiEleU-fi .1] 3 _fl 3 = 153,:3-1fimm _ _ gamedmnm _ I} _ 50 = lafle—Lfiflflflt _ EDGE—want . rfi = 2“ x 10-54“ H. a at : DC lU—a':_2l11000E—Efiimnt m EUUUe—JHJDUE} : _BUUe—lfi:{lflflf ___ age—WEIR 1i“; “a = L}: — EFL {laflfi—ififlflflf _ EDGE—WUUE} _ I:_EUUE—lfi;flflflt _ SUE—MEN} Tang-Wm — ganja-“mm 1-1 t r: U ...
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hw5_sol - (LT! ('41 «00 = —(0.5 X 1040103000) 2 —5 V...

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