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Unformatted text preview: so we can split the series into two series.) X n =1 1 6 ! 1 6 ! n1 + X n =1 1 3 ! 1 3 ! n1 = 1 / 6 11 / 6 + 1 / 3 11 / 3 = 1 5 + 1 2 = 7 10 4. Determine whether the sequence is convergent or divergent. If it is convergent, nd the limit. 3 + 5 n 2 n + n 2 n =1 lim n 3 + 5 n 2 n + n 2 = lim n (3 + 5 n 2 )1 /n 2 ( n + n 2 )1 /n 2 = lim n 3 /n 2 + 5 1 /n + 1 = 0 + 5 0 + 1 = 5 Have a good Spring Break! Remember not to drink and derive (or integrate)....
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This note was uploaded on 07/11/2011 for the course MAC 2312 taught by Professor Bonner during the Spring '08 term at University of Florida.
 Spring '08
 Bonner

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