7_Problem CHAPTER 9

7_Problem CHAPTER 9 - PROBLEM 9.6 CONTINUED For the second...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
PROBLEM 9.6 CONTINUED For the second integral use substitution 1 1, ( 1 ) y ud u d y y b u bb = −⇒ = = − 01 0 yu ybu = = = = Now 1 2 22 2 00 1( 1 ) y yd y b u u d u b  −=   ∫∫ 35 3 5 7 1 2 2 2 2 0 0 33 1 1 242 2 357 buu u d u b u u u =− + + 3 7 08 43 0 1 6 1 0 5 1 0 5 b −+ =+ + = = Then 3 16 51
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online