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12_Problem chapter 2 - Gm hawk(32071 «scorn F1®3MWITUJE...

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Unformatted text preview: Gm...- hawk-(32071)} «scorn; F1®3MWITUJE PrND vIREC-TIOH or f GIVEN: F: 23cm, 01525: 5:4“: FA>0 f_INLb’-La) F Ann FA, (363ml: 91. mw—-« n...— .._..._‘_ K'—........._—u—.—---.-ham—u:- F If” F “TA—FF” =IIQ-60)"+(320)‘+(aoo)” quooN'<I (a) F- - Fcoba : (130907105325 @391?“ 4 1 F F’? . (axon) :(Iymonr'q- sou)‘+ a _£:_Zflfi-; .2339 a = 73 2° 4 F: F‘+ + , w” 0 F 400 H o " . F _+-J 23n)‘-{Iqu‘— (an? F; =+IOB.D N d. 3 N ___ = = . gas a :5 F izl—qfifi-fi (15556 at? ”DIE ‘ (1)) ma: mfg/F5'6D/150'" _::::;: E‘— [60253. = 7 - me 230: + - - as 51:..FE_:M= 0.8387 9‘227'3 ‘ CUBE: EIIF / (icon GIVEN: F:210N F- ”sou BA- -ISLz .I—LmuLmflfl-un— 2. so I §___N_' F: (320m +000»); (250:95 (G)F:FC0593=(2I014ILII5\5\1' FINE- MHGNITUDE Ah”) DIRECTION. OF 1". F‘- = F: +131. “Ti; GLEN)!" (BO Nr+131+ (‘IS¥0N)L F'— _— I—m ._ g._ z -— D“ ‘ F317? +F'A Hr}- - (310}‘+(‘Ioo)"+(15‘h)‘. F: New 7‘ 5‘ "’ 27mm; “3“) F 7,2 4 (Bang: fi/F:801110:+0.5BID 9‘ ”7' coma-a Efrz-am/zmr 33: 101.2 ‘ _J.1fl_ : - CD59: F— 57m: 055w 91 55,3 «1 GIVEN: mama IN CABLE AB I5 H-OBNv 'FII-IJJ: cuHPost 0F Fonz: mam on Iveu: FORCE wm a: 5-73" 6 257.3" A? AND F =—I‘II+ 0 |b FINDJLQ B . (19F “Fa; mm F. ..._._—__.-._____ . (a) To DETERMINE 96 cos 61‘1- cos 03 Has 193:, Casey: hassltaa-cufl‘ WE 055 THE RELHTTDIJ .p—_—___..————_...— 39 = 516L+HBO§— 360k Ba- (32:: +(Ieo)‘+(56d‘-680 f: Fa = fi_ 1+0_8____N [Igzomn)I_.+(tIaom-)_a.-(sbom)fl sum-E F3 (0, we Mus-r amt C95ea40, TH'UJ'. cos 53:“ \II- m’64.3'-Co5‘5'7.9.:-0.7699, 63:”03” ‘ ~an BR 680mm (b) F: :: '1“'°-”=:zzs.o II» F; m I6 4 f: (1‘? “WHEN; WW)" (mag marge r: flaw, -r=+2san, F=- 2,16” ‘ Ff page: (116.0 1b)ch 51,3” 5:113 ”7 d * J i .._ = .oI c 5513' =I2mlb F; Foot; 9A (21:. b) o F; 4 5M»: A mum IN as“: 2.82 I G-‘IVEN FORCE WITH @57ng arm”? in IS LIZ? HI FIND — 52,9 lb 250 FIND: —- — — —— I commem a? FORCE EXERTED on Same fl <0l we mar Haw: cos. 9A <0. THUS: Loses-Washes"cns’IuI.rI'=-o.me, 93mm" ‘ _ _ (“fig-17%;”.— noon. F=IIolb 4 fl ‘Q::A"3°3*5‘°L< M= mmmh :60 . E 52‘,“ F§A= £%YF1§DM§+CHHDMI+BM)E] Ff Fcosa =(H0.01b)Cos 70.4 F 235,0”, ‘ Ff F x f=_(u.s u)}+(3Ia.au);+-(zs7.a my: cos I _ Bf (me “7305 “H. ‘I III-"90.015 4 I1: 455 N, FA=+5I1 n, fizrzaefl d 19 ...
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