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15_Problem chapter 2 - 2.99 CONTINUED Gwan TAB 259 N FIND...

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Unformatted text preview: 2.99 CONTINUED Gwan: TAB: 259 N FIND: VEant FORCE _‘P EXERTED HT A BY THE BflLLouN- MHKIMG 1'”: 15?»! w $42.0) MJ‘D soLVINrr F0“ Tfic" nc=%%_(0.(7x159~) TA;:‘+1?.I5’N CARR-(ms m-ro amt?) Au» sowms- FOR 1333‘ T —25: .figzwnnw) Tng=53516w “D- a: SussTWTIHG m T "Qua? mr-ro (0mm 50mm, :lQSLBfl He.- FoR 7?: a _ P.— o.8(25qy)+%(+71.15w)+ -:—";-('255.5&N) f=ibam1 «I 2.100 I GWEN: TM: W. n @EE Fm,“ 5342; VVBRTICH-L FORCE f txaam» ma LEFT) n? n 31 we ammo-1 Flb. P 2.99, Piling. 152.101] RM!) 132.102 ‘51; umfinflcfiwrpoa BERTIJTW 0F EHSL‘LU-IGD ”NONE Tm= 441 N ”J ans. (1) map (3) MD «owns, FM Tm Am TAD : ,55 410mm — — “H" — ' _ 1H q_ T ,._____ FREE Bow: A Tw'mw If”) I m: 33' 7* Tflrilrofl Tflp=4qmw SUBSTITUWNG FOR TM .EC’TFD INTO (2) MEDLVIIJG “if" Foliqzs RPf’LIE’D m- A w ... hRE T 1 'AB ’ ’nc ’ 339 ’ Mb ?, vim-ZR: E= Pd. To ExPatss TH-E an??? FORCE: ml rents 0F TH! UNI-r vzc‘rares, WEWRiTE pigs-(2'10 ”3+ Eémwhiéfmmssflflfié N as f: €56 H 1 4 (SEE mm: o»: up?“ LE‘F‘E) GIVEN: Tab = #8”! END: VERTICAL FDRcE f Exrfirw m- H 8"“ T“ .____.._.__—__._-._ EEE fE‘Frt—mun CHAMH run DERIVRTloH' o‘F r515.(l),(1),C5}. EHUDDN. _..._4 K} : -(Io.zom)§ - (5150...); 95: 7.00 M AC 2 (2.150’“)! ’(5.‘Dm)&rf-('+.20m)§, Ac: 7.9-0»! _. M! = — (5.50”); 43.5%); ma.- 6.50m HHKWC— Tnn= 43m I" EM?) MD 6:»va PM 77m: .. 'r efliilraw 7:11:12er “"- H2 551 J *c 5 CfiRR'r'WG- mm mg) RM) Sou/HUG ran my fl (1:30.25 n) 7% =232.57 u TM = 0.55ch suasrmmmfi m: 733, 1;“? min} (1) Mr 5°“""‘* D Fbfl 9: P: 0.303257») +f—§('rso.25~J +32; (#8! ~}=,‘126-06H E=qzerJ1 4 EQUIHBEIUM CONDIT’JOII f : 1 T ‘l' ‘ — if 0 +~na*‘nn+?§' ”'0 T '95 [5215 FICrURE w uvm LEFT) .g' NEH: Batman exam FOREEf:BODN19TA. Ema: TENSION 1N EAcH CRBLE __ __ Susan-wrung TH-E E“)! Memo-45 oarmut» Fae I35, 0 1'“, MD Tm, mun Fae-roams- 3, Q, mm 5-. a q. r +%¥ Tm. )l' h..— ._--.._-..-nn..—-——-— SEE LE'T- H-fi-ND COLUMN Fun DEwa‘rIon oFmCl),(1},(3)' 'U 1"! ...- _ =-—— T firms-mgr” mm mu): 1‘ -é§|'_.‘r;¢_‘r,,(c Tnfmln TM sussnmra Foe 'r'M mo 1"” mm Emu.)- Ewan-nu; To zERo Tut CoEPF‘CIENT‘ 0‘“ Elé’fi.‘ — L“ _ .- 5“ 5s .. G) 0.5?" + 1"! TM - (I) 0,8(o.5"w§'f TM)___&” Tn: '65 (l- “1-; Tu} + no . _ .__._ a coal 1" = Q "O-BTAI ”finch—g: T +rp=0 (I 2 WIS-fiat: P 73¢ gar-1‘? #1. 571.6714 SUBSTJYUTE INTO FxPRtssmw Fan TM Min" TM: 0.5‘Hn(31r. (,1 M) £2130.qu TRD=LH74L37L61 N)=1HS'.SIM 133: m N, 7;; 372 N, Ta» = m AI CONTINUED 23 ...
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