Unformatted text preview: E . If the component is placed on the table so that half of its weight is supported by the system shown, determine the smallest allowable value of θ knowing that the maximum force each cylinder can exert is 8 kips. SOLUTION From the results of the Problem 10.13 cyl 2 sin 250 lb 9 16sin F = + Then ( ) 2 sin 8000 lb 250 lb 9 16sin = + or ( ) 2 2 32sin 9 16sin = + Thus, 2 9 sin 1008 = 5.42 = ° W...
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 Spring '08
 Jenkins
 Statics, Force, smallest allowable value, double scissor lift, 1000lb machine component

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