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Unformatted text preview: PROBLEM 9.14 CONTINUED
a 0 xe a dx = -axe
x -a a
0 - 0 -ae a
x -a x -a dx = -a 2e-1 - a 2e a 0 = -a 2e-1 - a 2e-1 + a 2e0 = -2a 2e -1 + a 2 Finally, I y = b -a 3e -1 + 2a -2a 2e-1 + a 2 = ba3 -5e-1 + 2 = 0.1606ba3 ( ) ( )
or I y = 0.1606ba3 ...
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.
- Spring '08