PROBLEM 10.23 Determine the value of θcorresponding to the equilibrium position of the mechanism of Problem 10.10 when 60 lbP=and 75 lb.Q=SOLUTIONFrom geometry 2 cos , 2 sinAAylylδθδ==−()2 sin, cos22CDlCDlVirtual Work: ( )0:0AUPyQCDδδ=−−=2sincos02PlQlθδθ−=or sin2cos/2QP=With 60 lb, 75 lbPQ==sin75 lb
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.