25_Problem CHAPTER 10

25_Problem CHAPTER 10 - PROBLEM 10.23 Determine the value...

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PROBLEM 10.23 Determine the value of θ corresponding to the equilibrium position of the mechanism of Problem 10.10 when 60 lb P = and 75 lb. Q = SOLUTION From geometry 2 cos , 2 sin AA yl y l δθ δ == () 2 sin , cos 22 CD l CD l Virtual Work: ( ) 0: 0 A UP y Q C D δδ = −− = 2s in co s 0 2 Pl Q l θδθ  =   or sin 2 cos /2 QP = With 60 lb, 75 lb PQ = = sin 75 lb
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