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PROBLEM 10.40
Solve Problem 10.39 assuming that
1.26 kips,
P
=
10 in.,
l
=
and
150 lb ft/rad
K
=⋅
. Obtain answers in each of the following quadrants:
09
0
,
θ
<<°
270
360 ,
°<
<
°
and 360
450 .
<
°
SOLUTION
Using Equation (1) of Problem 10.39 and
1.26 kip,
10 in., and
150 lb ft/rad
Pl
K
==
=
⋅
we have
()
10 in.
1260 lb
12 in./ft
cos
150 lb ft/rad
=
⋅
or
7
or
7cos
cos
(1)
The solutions to this equation can be shown graphically using any appropriate graphing tool, such as Maple,
with the command:
{ }
plot
theta, 7 * cos theta
,
0..5 * Pi/2 ;
t
=
Thus, we plot
and
7cos in the range
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.
 Spring '08
 Jenkins
 Statics

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