46_Problem CHAPTER 10

46_Problem CHAPTER 10 - PROBLEM 10.43 For the linkage...

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PROBLEM 10.43 For the linkage shown, determine the force P required for equilibrium when 40 N m. M =⋅ SOLUTION For bar ABC, we have where 375 mm 2 c y a a δ δα == and for bar CD , using the Law of Cosines 222 2c o s 5 5 CD C D aLL L L = +− ° Then, noting that constant, a = we have ( ) ( ) 0 2 2 2 cos55 2 CC DD C D LL L L δδ =+− ° ° Then, because : Ly =− ( ) ( ) cos55 cos55 C DC D y L −° = For the given position of member CD , CDE is isosceles. and 2 cos55 La L a ° Then () ( ) 2 o s 5 5 c o s 5 5 o s5 5 aay a a L °− ° = ° or 2 cos55 12 c o s 5 5 ° =
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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