73_Problem CHAPTER 10

73_Problem CHAPTER 10 - PROBLEM 10.66 Using the method of...

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Unformatted text preview: PROBLEM 10.66 Using the method of Section 10.8, solve Problem 10.38. SOLUTION Spring where VSP = yC = d AC tan VSP = 1 2 kyC 2 d AC = 15 in. 1 2 kd AC tan 2 2 VP = - PyP Force P : where yP = r r = 3 in. VP = - Pr Then V = VSP + VP = 1 2 kd AC tan 2 - Pr 2 Equilibrium or or Solving numerically, dV 2 = 0: kd AC tan sec2 - Pr = 0 d ( 4 lb/in.)(15 in.)2 tan sec2 - ( 96 lb )( 3 in.) = 0 3.125 tan sec 2 - 1 = 0 = 16.4079 = 16.41 ...
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