PROBLEM 9.79 CONTINUED
(
a
)
4
4
4
5
3
1
45 :
cos90
sin90
16
16
2
x
I
a
a
a
θ
π
π
′
= +
°
=
−
° −
°
4
or
0.482
x
I
a
′
=
W
4
4
5
3
1
cos90
16
16
2
y
I
a
a
π
π
′
=
+
° +
4
or
1.482
y
I
a
′
=
W
4
4
3
1
sin90
cos90
16
2
x y
I
a
a
π
′ ′
= −
° +
°
4
or
0.589
x y
I
a
′ ′
= −
W
(
b
)
30 :
θ
= −
°
(
)
(
)
4
4
4
5
3
1
cos
60
sin
60
16
16
2
x
I
a
a
a
π
π
′
=
−
−
°
−
−
°
4
or
1.120
x
I
a
′
=
W
(
)
(
)
4
4
4
5
3
1
cos
60
sin
60
16

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- Spring '08
- Jenkins
- Statics
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