PROBLEM 9.105 The moments and product of inertia for an L102 ×76 ×6.4-mm angle cross section with respect to two rectangular axes xand ythrough Care, respectively, 640.166 10 mmxI=×, 0.453 10 mmyI, and 0xyI<, with the minimum value of the moment of inertia of the area with respect to any axis through Cbeing min0.051 10 mmI. Using Mohr’s circle, determine (a) the product of inertia xyIof the area, (b) the orientation of the principal axes, (c) the value of maxI. SOLUTION Given: 0.16610 mm , 0.45310 mm and 0xyxyIII=×=×<Note: A review of a table of rolled-steel shapes reveals that the given values of xIand yIare obtained when
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