155_Problem CHAPTER 9

155_Problem CHAPTER - PROBLEM 9.125 CONTINUED Now dI y = dI BB,mass dI DD,mass = 1 xz x 2 z 2 dy 12 2 1 y ab 1 a 2 b 2 12 h = 2 y 1 dy h Have Then

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PROBLEM 9.125 CONTINUED Now ,mass ,mass yB B D D dI dI dI ′′ =+ ( ) 22 1 12 x zx z d y ρ () 1 11 12 yy ab a b dy hh  + +   Have 4 1 1 62 y my m abh dI a b dy =⇒ = + + Then 4 0 1 2 h I dI a b dy == + + ∫∫ 0 5 1 25 h mh y ab × + ( ) () ( ) 55 1 10 m 1 or 10 y
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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