PROBLEM 9.136 A square hole is centered in and extends through the aluminum machine component shown. Determine (a) the value of afor which the mass moment of inertia of the component with respect to the axis ,AA′which bisects the top surface of the hole, is maximum, (b) the corresponding values of the mass moment of inertia and the radius of gyration with respect to the axis .AA′(The density of aluminum is 32800 kg / m .) SOLUTION First note 211mVbLρρ==And 222mVaL(a) Using Figure 9.28 and the parallel-axis theorem, have ( ) ( )12AAAAAAIII′′′=−()21122ambbm=++
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.