191_Problem CHAPTER 9

191_Problem CHAPTER 9 - PROBLEM 9.142 CONTINUED and dm = dV...

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PROBLEM 9.142 CONTINUED and copper g dm dV td dx γ ρζ == Then () copper 22 2 00 2 cos 30 g La y I tx d d x ζζ =∫ + ° copper 23 2 0 1 cos 30 g3 L ta x a d x  + °   copper 33 2 1 cos 30 3g L aL A a L =+ ° = ( ) 2 2 1 cos 30 3 mL a = 2 2 11 0.092422 lb s /ft 4 cos30 ft 32 =⋅ + ° 498.69 10 lb ft s = ×⋅ Finally, ( ) 500.62 498.69 10 lb ft s y I = or 999 10 lb ft s y I = W ( ) ( ) 12 zz z I II where 2 2 1 14 8 0.092422 lb s /ft ft 31 2 z I
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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