To the Instructor: The following formulas for the mass of inertia of a semicylinder are derived at this time for use in the solutions of Problems 9.144–9.147. From Figure 9.28 Cylinder: ()2cylcyl12xIma=() ()( )22cylcylcyl1312yzIImaL==+Symmetry and the definition of the mass moment of inertia 2Irdm=∫imply semicylindercylinder12II=2cylsc11xI∴=and cylscsc3212IaL+However, sccyl12mm=
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.