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202_Problem CHAPTER 9

# 202_Problem CHAPTER 9 - PROBLEM 9.147 CONTINUED 2 2 16 4...

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PROBLEM 9.147 CONTINUED ( ) ( ) ( ) ( ) 2 2 2 2 3 2 2 2 3 1 16 4 0.5 1ft 5.1874 10 lb s /ft 0.5 0.5 6 in 2 3 12 in. 9 x I π π × = × + + + × 3 2 1.40209 10 lb ft s = × ( ) ( ) ( ) ( ) 2 2 2 2 3 2 2 4 1 4 0.5 1ft 10.8451 10 lb s /ft 3 1.4 0.4 6 in 12 3 12 in. x I π × = × + + × × 3 2 0.38736 10 lb ft s = × Then ( ) 3 2 4.1585 4.7089 1.40209 0.38736 10 lb ft s x I = + + × 3 2 9.8821 10 lb ft s = × or 3 2 9.88 10 lb ft s x I = × W ( b ) Have ( ) ( ) ( ) ( ) 1 2 3 4 y y y y y I I I I I = + + where ( ) ( ) ( ) ( ) 2 2 2 2 2 3 2 2 1 1 3 4 1ft 105.676 10 lb s /ft 3 4 in 12 2 2 12 in. y I = × + + + × 3 2 6.1155 10 lb ft s = × ( ) ( ) ( ) ( ) ( ) ( ) 2 2 2 2 2 3 2 2 2 1 1ft 26.419 10 lb s /ft 1.5 2 0.75 5 in 12 12 in. y I = × + + + × 5 2 4.7854 10 lb ft s = × ( ) ( ) ( ) ( ) ( ) 2 2 2 2 2 3 2 2 2 3 1 16 1 4.05 1ft 5.1874
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