213_Problem CHAPTER 9

213_Problem CHAPTER - PROBLEM 9.152 Determine the products of inertia I xy I yz and I zx of the steel machine element shown(The specific weight of

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PROBLEM 9.152 Determine the products of inertia , xy I , yz I and zx I of the steel machine element shown. (The specific weight of steel is 3 0.284 lb/in . ) SOLUTION First compute the mass of each component mV g γ = Then () 3 2 1 2 0.284 lb/in 5 in. 4.5 in. 0.9 in. 0.1786 lb s /ft 32.2 ft/s m × = 3 2 2 2 0.284 lb/in 3 in. 2.5 in. 0.8 in. 0.05292 lb s /ft 32.2 ft/s m × = 3 2 2 3 2 0.284 lb/in 0.6 in. 0.5 in. 0.0049875 lb s /ft 32.2 ft/s m π  =   Now observe that the centroidal products of inertia, ,, x yy z I I ′′ and , zx I ′ ′ of each component are zero because of symmetry. Now uv u v I Im u v =+ so that body . uv I mu v 2 ,lb s /ft m ,ft x y z 2 lb ft s mx y 2 lb ft s my z
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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