225_Problem CHAPTER 9

# 225_Problem CHAPTER 9 - PROBLEM 9.158 CONTINUED Thus I xy =...

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PROBLEM 9.158 CONTINUED Thus xy I mx y 111 2 2 2 33 3 mxy mx y =− + () 32 0.6 1.8 15.2174 10 lb s /ft ft ft 12 12    4 1.8 1ft 1.8 3.5855 10 lb s /ft 2.4 in. ft 31 2 i n . 1 2 π  × −× ×   ( ) 62 114.131 73.326 10 lb ft s × ⋅⋅ or 187.5 10 lb ft s xy I = W Now 2 22 333 yz I my z m y z m y z m y z = + or 0 yz I = W Also ( ) ( ) 123 zx zx zx zx I III =−+ ( ) 3 zx mzx I + Now determine 3 zx I Have ( ) 3 3 zx z x dI dI z x dm ′′ =+ 2 sT x z txd z g γ ( ) 22 3 1 2 sT tz a z dz g Now 2 33 4 sT mt a g γπ = or 3 2 3 4 sT m t g a = Therefore, 23 2 2 4 0 3 0 1 1 24 a a zx mm Ia z z d z a z z aa ππ = 2 1 2 ma Finally
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## This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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